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DNA Replication and Gene Expression (AAMC 1B)

This page follows genetic information from the double helix to a folded protein: how DNA is copied and proofread, how damage is repaired, how a gene is transcribed and processed into mRNA, how ribosomes translate the code, and how cells decide which genes to switch on. On the MCAT these ideas show up in nearly every Bio/Biochem passage that involves a mutation, a knockout, a reporter gene or a drug that blocks a step of the central dogma.

AAMC content category 1B. Subtopics: DNA replication, DNA repair, transcription, RNA processing, the genetic code and translation, prokaryotic gene regulation (operons) and eukaryotic gene regulation. For nucleic acid structure see Biomolecules; for PCR, cloning and blotting see Biotechnology and Lab Techniques.

The Central Dogma at a Glance

The central dogma says information flows DNA → RNA → protein. DNA is copied by replication, read into RNA by transcription, and decoded into a polypeptide by translation. Retroviruses add a reverse step (RNA → DNA, by reverse transcriptase), and some RNA viruses copy RNA directly (RNA-dependent RNA polymerase), but the core direction for cellular genes never changes: protein sequence is never copied back into nucleic acid.

Directionality rule (memorize this once)

Every nucleic acid polymerase reads the template 3′ → 5′ and builds the new strand 5′ → 3′, adding each nucleotide to a free 3′-OH. The energy comes from cleaving the incoming nucleoside triphosphate, releasing pyrophosphate (PPi), which is then hydrolyzed to make the reaction effectively irreversible. Ribosomes read mRNA 5′ → 3′ and build protein N-terminus → C-terminus.

DNA Replication

Replication is semiconservative: each daughter helix keeps one parental strand and gains one new strand. Meselson and Stahl showed this by growing bacteria in heavy 15N, switching to 14N, and finding a single intermediate-density band after one generation, then intermediate plus light bands after two.

Origins and the replication fork

Bacteria usually have one circular chromosome with a single origin (oriC), so replication runs bidirectionally until the two forks meet. Eukaryotic chromosomes are linear and much longer, so they use many origins at once. Each origin opens into a replication bubble with two forks moving in opposite directions.

Proteins at the replication fork
ProteinJobExam detail
HelicaseUnwinds the double helix by breaking hydrogen bonds between basesUses ATP; opens the fork
Single-strand binding proteinsCoat exposed single strandsPrevent re-annealing and protect from nucleases
Topoisomerase (gyrase in bacteria)Relieves supercoiling ahead of the fork by cutting and rejoining DNATarget of fluoroquinolone antibiotics and some anticancer drugs
PrimaseLays down a short RNA primerDNA polymerase cannot start a chain from scratch; it needs a 3′-OH
DNA polymerase III (prokaryotes); δ and ε (eukaryotes)Main synthesis of new DNAHighly processive; 3′ → 5′ exonuclease proofreading
DNA polymerase I (prokaryotes)Removes RNA primers and fills the gaps with DNAHas 5′ → 3′ exonuclease activity; in eukaryotes RNase H and FEN1 do this
DNA ligaseSeals nicks in the sugar-phosphate backboneJoins Okazaki fragments into a continuous strand
TelomeraseExtends chromosome ends using its own RNA templateA reverse transcriptase; active in germ cells, stem cells and most cancers

Leading and lagging strands

Because new DNA can only grow 5′ → 3′, the two template strands are copied differently. The leading strand is made continuously toward the fork from one primer. The lagging strand is made away from the fork in short pieces called Okazaki fragments (roughly 1,000 to 2,000 nucleotides in bacteria and 100 to 200 in eukaryotes), each with its own RNA primer. The primers are later replaced with DNA and ligase joins the pieces.

Fidelity

Base pairing alone would give roughly one error per 104 to 105 nucleotides. Proofreading by the polymerase's 3′ → 5′ exonuclease lowers this about a hundredfold, and post-replication mismatch repair lowers it further, to roughly one error per 109 to 1010 nucleotides overall.

The end-replication problem and telomeres

On a linear chromosome, the final RNA primer at the very end of the lagging strand cannot be replaced with DNA, so each round of replication would shorten the chromosome. Telomeres are repetitive non-coding sequences (TTAGGG repeats in humans) that act as a buffer. Telomerase extends the 3′ overhang; somatic cells with little telomerase shorten their telomeres with each division, which contributes to replicative senescence.

Common trap. "Proofreading" means the 3′ → 5′ exonuclease of the polymerase removing a wrong base it just added. Primer removal in bacteria uses the 5′ → 3′ exonuclease of DNA polymerase I. Students often swap the two directions. Also: primase makes RNA, so primers contain uracil, not thymine.

DNA Repair

DNA is damaged constantly by spontaneous chemistry (deamination, depurination), reactive oxygen species, UV light and chemicals. Repair pathways are matched to the type of damage. Defects in these pathways raise mutation rates and cancer risk, which is why passages often pair a repair gene with a hereditary cancer syndrome.

Major DNA repair pathways
PathwayDamage fixedHow it worksLinked condition
Mismatch repairWrong base pairs missed by proofreadingRecognizes the newly made strand (in E. coli, it is not yet methylated), cuts out a stretch and resynthesizes itLynch syndrome (hereditary nonpolyposis colorectal cancer)
Base excision repairSingle damaged or wrong bases (e.g., uracil from cytosine deamination)A glycosylase removes the base, an endonuclease cuts the backbone, polymerase and ligase fill inRare syndromes; key for oxidative damage
Nucleotide excision repairBulky, helix-distorting lesions such as UV-induced thymine dimersExcises an oligonucleotide around the lesion, then fills the gapXeroderma pigmentosum (extreme UV sensitivity)
Homologous recombinationDouble-strand breaks, after S phaseUses the sister chromatid as an accurate templateBRCA1 and BRCA2 mutations
Non-homologous end joiningDouble-strand breaks, any phaseLigates ends directly; fast but can delete or add basesAlso used in V(D)J recombination in lymphocytes

Mutation types to name on sight

Transcription

Transcription copies one strand of a gene into RNA. The strand that RNA polymerase reads is the template (antisense) strand; the RNA has the same sequence as the coding (sense) strand, with U in place of T. RNA polymerase does not need a primer and has no proofreading exonuclease, so transcription is less accurate than replication, but errors are not inherited.

Initiation, elongation, termination

Eukaryotic RNA polymerases
EnzymeLocationMain products
RNA polymerase INucleolusLarge rRNAs (28S, 18S, 5.8S)
RNA polymerase IINucleoplasmmRNA precursors (hnRNA), most snRNAs, miRNAs
RNA polymerase IIINucleoplasmtRNA, 5S rRNA

RNA Processing in Eukaryotes

Bacterial mRNA is used as soon as it is made; transcription and translation are coupled in the cytoplasm. Eukaryotic primary transcripts are modified in the nucleus before export:

Common trap. Introns are removed, exons are expressed, but exons are not all protein-coding: the 5′ and 3′ untranslated regions (UTRs) are exonic too. Also, cDNA made from mature mRNA by reverse transcriptase lacks introns, which is why a human gene cloned from cDNA can be expressed in bacteria that cannot splice.

The Genetic Code and Translation

Features of the code

Writing the mRNA from a template strand

Template: 3′-TAC GGA TTC-5′. Pair each base and flip the orientation label: mRNA 5′-AUG CCU AAG-3′. The coding strand reads 5′-ATG CCT AAG-3′, identical to the mRNA except T for U. Always write sequences 5′ → 3′ before you look up codons.

The players

Steps

Energy bookkeeping: charging a tRNA costs 2 high-energy bonds (ATP → AMP), entry to the A site costs 1 GTP and translocation 1 GTP, so roughly 4 high-energy bonds per peptide bond.

After translation

Proteins may be folded with chaperones, cleaved (proinsulin to insulin), or modified by phosphorylation, glycosylation, acetylation, lipidation or ubiquitination. Proteins with an N-terminal signal sequence are made on ribosomes docked to the rough ER by the signal recognition particle and enter the secretory pathway.

Prokaryotic Gene Regulation: Operons

An operon is a cluster of genes under one promoter and one operator, transcribed as a single polycistronic mRNA. A repressor protein binds the operator and blocks RNA polymerase.

lac operon (inducible, catabolic)

Genes lacZ (β-galactosidase), lacY (permease), lacA (transacetylase). No lactose: the LacI repressor binds the operator, so transcription is off. Lactose present: allolactose binds the repressor and releases it from the operator. Glucose low: cAMP rises, cAMP binds CAP (catabolite activator protein), and CAP-cAMP binds near the promoter to boost RNA polymerase binding. Maximal transcription needs lactose present and glucose absent. This glucose preference is called catabolite repression.

trp operon (repressible, anabolic)

Encodes enzymes that make tryptophan. The repressor is made inactive; when tryptophan is abundant, it acts as a corepressor, binds the repressor and activates it, shutting the operon off. A second layer, attenuation, uses ribosome stalling on the leader sequence to decide whether a terminator hairpin forms, which is possible only because bacterial transcription and translation are coupled.

Mutant logic trap. A mutant operator that cannot bind repressor (Oc) gives constitutive expression only of genes on the same DNA molecule: it is cis-acting. A mutant repressor gene affects operons anywhere in the cell because the protein diffuses: it is trans-acting. A repressor that cannot bind inducer (Is, "super-repressor") keeps the operon off even with lactose present.

Eukaryotic Gene Regulation

Eukaryotic control happens at many levels, from chromatin to protein lifespan.

Memory hook. "Acetyl opens, methyl closes." Histone acetylation opens chromatin for transcription; DNA methylation closes it. (Histone methylation can go either way depending on the residue, so the MCAT usually tests it only with passage support.)

Most lab techniques reuse the enzymes on this page. PCR borrows replication (primers, a heat-stable DNA polymerase, dNTPs). Reverse transcriptase turns mRNA into cDNA for cloning or RT-PCR. Restriction enzymes and ligase build recombinant plasmids, and reporter genes placed behind a promoter or enhancer reveal when that regulatory element is active. CRISPR-Cas9 makes a targeted double-strand break and then relies on the cell's own NHEJ (to knock genes out) or homologous recombination (to insert a template). Details are on the biotechnology notes.

Worked MCQs

Five MCQs on the patterns the exam returns to most often. Read every explanation, including the ones you got right.

Q1. E. coli cells are moved to a medium that contains lactose but no glucose. Which statement best describes the lac operon in these cells?

  • The repressor stays bound to the operator, so transcription is off
  • Allolactose releases the repressor and CAP-cAMP enhances promoter binding, so transcription is high
  • CAP-cAMP binds the operator and blocks RNA polymerase
  • Lactose acts as a corepressor that activates the repressor

With lactose present, allolactose binds the LacI repressor and removes it from the operator. With glucose absent, cAMP levels are high, so CAP-cAMP binds near the promoter and recruits RNA polymerase. Both conditions together give maximal transcription. Corepressors belong to repressible operons such as trp.

Q2. In E. coli, which enzyme removes the RNA primers from Okazaki fragments and replaces them with DNA?

  • DNA polymerase III
  • Primase
  • DNA polymerase I
  • DNA ligase

DNA polymerase I has a 5′ to 3′ exonuclease that removes RNA primers and fills the gap with DNA. Polymerase III does bulk synthesis, primase makes the primers, and ligase only seals the remaining nick in the backbone.

Q3. A DNA template strand reads 3′-TACGGA-5′. What is the sequence of the mRNA transcribed from it?

  • 5′-AUGCCU-3′
  • 5′-UCCGUA-3′
  • 5′-ATGCCT-3′
  • 5′-TACGGA-3′

RNA is antiparallel and complementary to the template, with U in place of T. Pairing 3′-TACGGA-5′ gives 5′-AUGCCU-3′, which begins with the start codon AUG. The option with T is the coding strand of DNA, not RNA.

Q4. A single base change converts the codon UAC (tyrosine) to UAA. This mutation is best classified as:

  • Silent
  • Missense
  • Frameshift
  • Nonsense

UAA is a stop codon, so translation ends early and a truncated protein results: a nonsense mutation. A single substitution cannot shift the reading frame, and the amino acid is not swapped for another one (missense) or kept the same (silent).

Q5. Patients with xeroderma pigmentosum develop skin cancers after minimal sun exposure. Which repair pathway is most likely defective?

  • Mismatch repair
  • Nucleotide excision repair
  • Base excision repair
  • Non-homologous end joining

UV light creates thymine (pyrimidine) dimers, bulky lesions that distort the helix. These are removed by nucleotide excision repair. Mismatch repair fixes replication errors, base excision repair fixes single damaged bases, and NHEJ fixes double-strand breaks.

Quick Recap

Test yourself. Take a timed practice test or browse topic-wise MCQs to lock these concepts in.