Thermochemistry and Energetics
Thermochemistry is the study of heat changes that accompany physical and chemical processes. For the MCAT you should know the vocabulary (system, surroundings, state functions), the first and second laws of thermodynamics, the difference between ΔU and ΔH, calorimetry (q = mcΔT), Hess's law and bond enthalpies, and—most heavily tested of all—entropy (S) and Gibbs free energy (ΔG = ΔH − TΔS) as the predictor of spontaneity.
Thermodynamics
Thermodynamics is the branch of science that deals with energy changes accompanying physical and chemical processes, especially the inter-conversion of heat and work. Chemical thermodynamics applies these ideas to chemical reactions; the predictions are independent of the path or the rate.
System / Surrounding / State Function Terms
- System
- The portion of the universe under study (e.g. the chemicals in a beaker).
- Surroundings
- Everything outside the system that can interact with it.
- Boundary
- The real or imaginary surface separating system from surroundings.
- Open system
- Exchanges both matter and energy with surroundings (e.g. boiling water in an open pan).
- Closed system
- Exchanges only energy, not matter (e.g. a stoppered flask).
- Isolated system
- Exchanges neither matter nor energy (e.g. a perfect thermos flask — an idealization).
- State function
- Property whose value depends only on the present state of the system, not on how it got there. Examples: U, H, S, G, T, P, V.
- Path function
- Property whose value depends on the path taken between states. Examples: q (heat) and w (work).
- Standard state
- Pure substance at 1 atm (101.3 kPa) and a specified temperature, conventionally 298 K. Quantities measured under these conditions are denoted by a degree sign, e.g. ΔH°.
Internal Energies
The internal energy U of a system is the total energy stored in it — the sum of the kinetic energies of all particles plus the potential energies of all interactions (intermolecular forces, bonds). U is a state function. Its absolute value cannot be measured, but changes ΔU can.
For a chemical reaction at constant volume in a closed system, the heat absorbed equals ΔU:
ΔU = qv (no expansion work)
This is what a bomb calorimeter measures.
First Law of Thermodynamics
The first law is the principle of conservation of energy applied to thermodynamic systems: energy can be transformed from one form to another but cannot be created or destroyed. Mathematically:
ΔU = q + w
Sign convention (IUPAC):
- q > 0 — heat absorbed by the system.
- q < 0 — heat released by the system.
- w > 0 — work done on the system (volume decreases).
- w < 0 — work done by the system on surroundings (expansion).
For pressure-volume (expansion) work at constant external pressure: w = −Pext ΔV.
Enthalpy
Enthalpy H is defined as H = U + PV. Like U, H is a state function. The change in enthalpy at constant pressure equals the heat absorbed:
ΔH = qp
This is why most laboratory reactions in open vessels are described by ΔH, not ΔU.
Relation between ΔH and ΔU
For reactions involving gases: ΔH = ΔU + ΔngasRT, where Δngas = (moles of gaseous products) − (moles of gaseous reactants). For reactions with no change in moles of gas, ΔH ≈ ΔU.
Standard enthalpy changes
| Type | Symbol | Definition | Sign |
|---|---|---|---|
| Formation | ΔH°f | Forming 1 mol of compound from elements in standard states | Usually −ve (some +ve, e.g. NO) |
| Combustion | ΔH°c | Complete combustion of 1 mol in excess O2 | Always −ve |
| Neutralization | ΔH°neut | 1 mol H2O formed from H+ + OH− (dilute) | ~ −57 kJ/mol (strong acid + strong base) |
| Solution | ΔH°sol | 1 mol solute dissolved in excess solvent | Can be + or − |
| Atomization | ΔH°at | 1 mol of gaseous atoms formed from element | Always +ve |
| Bond enthalpy | ΔH°BE | Energy to break 1 mol of a specific bond in gas phase | Always +ve |
| Lattice enthalpy | ΔH°L | 1 mol of ionic solid formed from gaseous ions | Always −ve (release of energy) |
| Hydration | ΔH°hyd | 1 mol of gaseous ions dissolved in water | Always −ve |
| Fusion / vaporization | ΔH°fus / ΔH°vap | 1 mol melted / vaporized | +ve (endothermic phase changes) |
Calorimetry
Calorimetry measures heat flow from the temperature change of a known mass of water (or other substance). The core MCAT equation is:
q = m c ΔT
where q is heat (J), m is mass (g), c is the specific heat capacity (J g−1 °C−1; for water c = 4.18 J g−1 °C−1), and ΔT = Tfinal − Tinitial. If molar heat capacity C is used, q = n C ΔT.
- Bomb calorimeter — constant volume; the heat released equals ΔU (qv). A sealed steel "bomb" is surrounded by a water bath and ΔT is measured; q = (m c ΔT)water + CcalΔT.
- Coffee-cup (open) calorimeter — constant pressure; the heat released equals ΔH (qp). qreaction = −qwater = −m c ΔT.
Exothermic and Endothermic Reactions
- Exothermic: system releases heat; ΔH < 0; products lie at lower energy than reactants. Examples: combustion (CH4 + 2O2 → CO2 + 2H2O, ΔH = −890 kJ mol−1), neutralization, respiration, condensation.
- Endothermic: system absorbs heat; ΔH > 0; products at higher energy. Examples: photosynthesis, melting, evaporation, decomposition of CaCO3, dissolving NH4NO3 (cold packs).
Hess's Law
Hess's law of constant heat summation (Germain Hess, 1840): the total enthalpy change for a reaction is independent of the route taken from reactants to products, provided the initial and final states are the same.
This is a direct consequence of enthalpy being a state function. It allows enthalpy changes that cannot be measured directly to be calculated from those that can.
General form
ΔHreaction = ΣΔH°f(products) − ΣΔH°f(reactants)
Example — formation of CO
The direct combustion C(s) + ½O2(g) → CO(g) cannot be measured cleanly because some CO2 always forms. Hess's law lets us combine:
- (i) C(s) + O2(g) → CO2(g); ΔH1 = −393.5 kJ
- (ii) CO(g) + ½O2(g) → CO2(g); ΔH2 = −283.0 kJ
(i) − (ii): C(s) + ½O2(g) → CO(g); ΔHf(CO) = ΔH1 − ΔH2 = −110.5 kJ.
Applications of Hess's law
- Calculating ΔHf of compounds that cannot be made directly from their elements.
- Calculating lattice energies via the Born–Haber cycle.
- Calculating bond enthalpies and resonance energies.
Bond Enthalpies
A bond enthalpy is the energy required to break one mole of a given bond in the gas phase; breaking bonds is always endothermic (+) and forming bonds is always exothermic (−). For a gas-phase reaction the MCAT lets you estimate ΔH from average bond enthalpies:
ΔHrxn = Σ(bonds broken) − Σ(bonds formed)
Note the sign carefully: this is "bonds broken minus bonds formed" (reactant bonds minus product bonds), the opposite ordering of the ΔH°f formula. Values are averages, so bond-enthalpy estimates are approximate.
Second Law and Entropy
The second law of thermodynamics states that the total entropy of the universe (system + surroundings) increases in any spontaneous process: ΔSuniverse = ΔSsystem + ΔSsurroundings > 0 for a spontaneous change, and = 0 at equilibrium.
Entropy S is a state function that measures the dispersal of energy and matter—often described as "disorder" or the number of accessible microstates. Units: J K−1 mol−1. The third law sets S = 0 for a perfect crystal at 0 K, so unlike H, absolute entropies (S°) can be tabulated.
- Entropy generally increases: solid → liquid → gas; dissolving a solid; heating; increasing the number of gas-phase molecules.
- ΔS°rxn = ΣS°(products) − ΣS°(reactants).
- Quick sign check: if a reaction produces more moles of gas, ΔSsystem > 0.
Gibbs Free Energy and Spontaneity
Combining the first and second laws gives the single most tested equation in MCAT thermodynamics—the Gibbs free energy, which folds both enthalpy and entropy into one spontaneity criterion at constant T and P:
ΔG = ΔH − TΔS (T in kelvin).
· ΔG < 0 → reaction is spontaneous (exergonic) in the forward direction.
· ΔG > 0 → non-spontaneous (endergonic); spontaneous in reverse.
· ΔG = 0 → system is at equilibrium.
Also: ΔG° = −RT ln K and ΔG = ΔG° + RT ln Q.
How the signs of ΔH and ΔS set spontaneity
| ΔH | ΔS | Spontaneity |
|---|---|---|
| − (exothermic) | + (more disorder) | Spontaneous at all temperatures (ΔG always < 0) |
| + (endothermic) | − (less disorder) | Non-spontaneous at all temperatures (ΔG always > 0) |
| − (exothermic) | − (less disorder) | Spontaneous only at low T (enthalpy-driven) |
| + (endothermic) | + (more disorder) | Spontaneous only at high T (entropy-driven) |
The crossover temperature at which a reaction switches between spontaneous and non-spontaneous is found by setting ΔG = 0, giving T = ΔH / ΔS.
Worked MCQs
Seven MCQs that capture the high-yield testing patterns for this chapter. Read the explanation even when you get the answer right — it's where the deeper concept lives.
Q1. Which of the following is NOT a state function?
U, H, S, G, T, P, V are state functions — they depend only on the current state. Heat (q) and work (w) are path functions; the same change in state can involve different q and w depending on how the change is carried out.
Q2. The first law of thermodynamics is mathematically expressed as:
The first law is the conservation of energy: ΔU = q + w (heat added to the system + work done on the system). The other equations are real, but describe Gibbs free energy, the ideal gas law, and the H−U relation respectively.
Q3. An exothermic reaction is one in which:
In an exothermic reaction the system loses heat to the surroundings, so ΔH < 0. Combustion, neutralization and respiration are textbook examples.
Q4. Hess's law is a direct consequence of:
Because H depends only on the initial and final states, the total ΔH for any path from reactants to products is the same. Hess's law allows you to add or subtract reaction enthalpies as if you were doing algebra.
Q5. For the reaction N2(g) + 3H2(g) → 2NH3(g) at 298 K, Δngas equals:
Δngas = (moles of gaseous products) − (moles of gaseous reactants) = 2 − (1 + 3) = −2. This is what enters ΔH = ΔU + ΔngasRT.
Q6. A reaction has ΔH = +50 kJ/mol and ΔS = +100 J K−1 mol−1. Above what temperature does it become spontaneous?
Set ΔG = ΔH − TΔS = 0 → T = ΔH / ΔS. Convert units: 50 000 J / 100 J K−1 = 500 K. With both ΔH and ΔS positive, the reaction is entropy-driven—ΔG becomes negative (spontaneous) only above 500 K.
Q7. For which process is ΔSsystem most clearly positive?
Entropy rises most when a gas is generated from a solid. Decomposition of CaCO3 creates a mole of CO2 gas from a solid, a large increase in disorder. The other three all decrease the moles of gas (or freeze a liquid), so ΔSsystem is negative.
Quick Recap
- State functions (U, H, S, G, T, P, V) are path-independent. q and w are not.
- First law: ΔU = q + w. At constant V: ΔU = qv; at constant P: ΔH = qp.
- Calorimetry: q = mcΔT; water c = 4.18 J g−1 °C−1. Bomb calorimeter → ΔU; coffee-cup → ΔH.
- ΔHrxn = ΣΔH°f(products) − ΣΔH°f(reactants); from bonds, ΔH = Σ(broken) − Σ(formed).
- Exothermic ΔH < 0; endothermic ΔH > 0. Hess's law: ΔHtotal is path-independent.
- Second law: ΔSuniverse > 0 for a spontaneous process; entropy rises solid → liquid → gas.
- ΔG = ΔH − TΔS: ΔG < 0 spontaneous, ΔG = 0 equilibrium, ΔG > 0 non-spontaneous. ΔG° = −RT ln K.
- Crossover temperature (spontaneity flips) at T = ΔH / ΔS.