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Fluid Dynamics

Fluids — liquids and gases — flow and transmit pressure. For the MCAT Chemical and Physical Foundations section, master density and pressure, hydrostatics (P = ρgh), Pascal's and Archimedes' principles, the continuity equation, Bernoulli's equation, and viscous (Poiseuille) flow. The exam loves to place these in biological contexts: blood pressure, circulation, IV drips, and gas exchange.

MCAT content mapping. Fluids appear under Foundational Concept 4 (physical principles in living systems): density, specific gravity, pressure (hydrostatic, gauge vs absolute), Pascal's principle, buoyancy/Archimedes, continuity, Bernoulli, viscosity/Poiseuille, and surface tension — often applied to the circulatory and respiratory systems.

Density, Specific Gravity & Pressure

Density ρ = m/V (SI: kg/m³). Water is 1000 kg/m³ (= 1 g/cm³). Specific gravity is the ratio of a substance's density to that of water; it is dimensionless. An object with specific gravity < 1 floats in water; > 1 sinks.

Pressure P = F/A is force per unit area normal to a surface (SI: pascal, Pa = N/m²). Pressure in a fluid acts equally in all directions at a given depth. Useful conversions: 1 atm = 1.013 × 105 Pa = 760 mmHg (torr) = 760 mm of Hg.

Hydrostatic pressure — gauge vs absolute

The pressure due to a column of fluid of depth h is the gauge pressure:

Pgauge = ρgh

The total or absolute pressure adds the pressure pushing down on the fluid surface (usually atmospheric):

Pabs = P0 + ρgh

Key point: hydrostatic pressure depends only on depth, fluid density, and g — not on the shape or total volume of the container (the "hydrostatic paradox"). A blood-pressure reading of 120/80 mmHg is a gauge pressure (above atmospheric).

Biological context. Because P = ρgh, blood pressure in the feet is higher than in the head when standing (the vertical column of blood adds ρgh). This is why fainting or lying flat restores blood flow to the brain, and why giraffes need very high mean arterial pressure.

Pascal's Principle

A pressure change applied to an enclosed incompressible fluid is transmitted undiminished to every point in the fluid and to the walls of the container. This is the basis of the hydraulic lift:

P1 = P2 ⇒ F1/A1 = F2/A2

A small force on a small piston produces a large force on a large piston (multiplied by A2/A1). Energy is conserved: the large piston moves a proportionally smaller distance, so F·d is unchanged.

Buoyancy & Archimedes' Principle

Any object immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces:

FB = ρfluid Vdisplaced g

Equation of Continuity

For an incompressible, non-viscous fluid flowing steadily through a pipe of varying cross-section, the mass flowing per second past every point is the same. Mathematically:

A1v1 = A2v2    (Av = constant)

Where A is the cross-sectional area and v is the speed of the fluid. This is a direct consequence of conservation of mass. Wherever the pipe narrows, the fluid must speed up; wherever it widens, the fluid slows down. The product Av is called the volume flow rate (m³/s).

Worked example

Water flows through a pipe whose radius narrows from 4 cm to 2 cm. If v1 = 2 m/s, then v2 = (A1/A2)v1 = (16/4)(2) = 8 m/s. Speed quadruples because area scales with r².

Bernoulli's Equation

For an ideal (incompressible, non-viscous, streamline) fluid, the sum of pressure energy, kinetic energy and potential energy per unit volume is constant along a streamline:

P + ½ρv² + ρgh = constant

P
Static pressure of the fluid (Pa).
½ρv²
Dynamic pressure due to fluid motion.
ρgh
Hydrostatic pressure due to height h above a reference level.

Direct consequence: where fluid speed is high, pressure is low (for flow at constant height). Combined with continuity (narrow → faster → lower pressure), this explains many MCAT scenarios.

Memory aid. "Faster flow → lower pressure." Where a vessel or pipe narrows, continuity forces the fluid to speed up, and Bernoulli says the pressure there drops.

Applications (MCAT-relevant)

Continuity vs Poiseuille — don't confuse them. Continuity/Bernoulli treat the fluid as ideal (non-viscous). In real vessels, viscosity dominates and the driving pressure drops along the flow (Poiseuille, below). The MCAT tests both frameworks; read the question to see whether viscosity matters.

Fluid Flow (Laminar, Turbulent)

Two distinct flow regimes occur in real fluids:

Laminar (streamline) vs Turbulent flow
PropertyLaminar / streamlineTurbulent
MotionSmooth, parallel layersChaotic, eddies and vortices
Velocity at a pointConstant in timeFluctuates rapidly
Mixing between layersNoneStrong
Energy lossLowHigh (dissipated as heat)
Reynolds number Re = ρvd/η< 1000 (transition 1000–2000)> 2000
Bernoulli applies?Yes (along a streamline)No
ExamplesSlow flow in narrow tubes, blood in capillariesSmoke from chimney, water from open tap, blood in aorta
Common trap. Bernoulli's equation strictly applies only to steady, non-viscous, incompressible, streamline (laminar) flow. Apply it to turbulent flow and your numerical answer will be wrong.

Fluid Drag

When a body moves through a fluid, it experiences a retarding force called drag. For a small spherical object moving slowly through a viscous fluid, Stokes' law gives the drag:

F = 6πηrv

where η is the coefficient of viscosity (Pa·s), r is the radius of the sphere, and v is its speed relative to the fluid. Drag rises linearly with speed at low Re, but for fast/large objects (turbulent regime) drag rises with v².

Coefficient of viscosity (η)

Viscosity is the internal friction of a fluid — resistance to shear. SI unit: Pa·s (or N·s/m²). For liquids viscosity decreases with temperature (e.g. honey thins on heating); for gases it increases with temperature.

Poiseuille's Law (Viscous Flow in Tubes)

For steady laminar flow of a viscous fluid through a rigid cylindrical tube, the volume flow rate Q depends strongly on the radius:

Q = πr4ΔP / (8ηL)

where ΔP is the pressure difference across the tube, r the radius, L the length, and η the viscosity. The dominant feature is the r4 dependence.

Surface Tension

Surface tension (γ, units N/m) arises because molecules at a liquid surface are pulled inward by cohesive forces, making the surface behave like an elastic membrane. It causes water droplets to bead, insects to walk on water, and capillary rise.

For a spherical bubble/droplet, Laplace's law gives the excess internal pressure ΔP = 2γ/r (droplet) or 4γ/r (soap bubble, two surfaces). Smaller radius → higher pressure.

Biological context. Alveoli in the lungs would collapse under high surface tension (small r → high ΔP). Pulmonary surfactant lowers γ, reducing the collapsing pressure and keeping small alveoli open — its absence causes infant respiratory distress syndrome.

Terminal Velocity

A body falling through a viscous fluid eventually reaches a constant speed when the net force on it is zero. At this point the weight is balanced by buoyancy plus the viscous drag. For a sphere of radius r, density ρ in a fluid of density σ:

vt = 2r²(ρ − σ)g / (9η)

Key features:

Why raindrops do not kill you

A raindrop reaches terminal velocity within metres of falling. For a 2 mm drop, vt ≈ 6–9 m/s. Without air drag a raindrop falling from 1 km would strike at >140 m/s.

Worked MCQs

Five MCQs that capture the high-yield testing patterns for this chapter.

Q1. Water flows through a pipe whose radius reduces from 4 cm to 2 cm. If the speed in the wider section is 1 m/s, the speed in the narrow section is:

  • 2 m/s
  • 4 m/s
  • 8 m/s
  • 16 m/s

By continuity A1v1 = A2v2. Areas scale with r², so A1/A2 = (4/2)² = 4, giving v2 = 4 × 1 = 4 m/s.

Q2. Bernoulli's equation is a statement of conservation of:

  • Mass
  • Momentum
  • Energy
  • Charge

P + ½ρv² + ρgh = constant expresses conservation of mechanical energy per unit volume of an ideal fluid along a streamline. Continuity, by contrast, is conservation of mass.

Q3. Stokes' drag on a small sphere of radius r moving slowly with speed v through a fluid of viscosity η is:

  • F = 4πηrv
  • F = 6πηrv
  • F = 6πηr²v
  • F = ηrv

Stokes' law: F = 6πηrv. Linear in radius and in speed; valid only at low Reynolds numbers (laminar regime).

Q4. A block floats in water with 90% of its volume submerged. Its density is approximately:

  • 100 kg/m³
  • 500 kg/m³
  • 900 kg/m³
  • 1100 kg/m³

For a floating object the submerged fraction equals ρobjectfluid. So ρobject = 0.90 × 1000 = 900 kg/m³. (An object denser than water could not float.)

Q5. Which condition is NOT required for Bernoulli's equation to be applied?

  • Steady flow
  • Incompressible fluid
  • Non-viscous fluid
  • Turbulent flow

Bernoulli's equation requires laminar (streamline) flow, not turbulent. The other three conditions are essential assumptions of the derivation.

Quick Recap

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